Lesson 3.7.1.2
3.7.1.2 Genetic crosses and inheritance patterns Quiz: AQA Biology, Unit 7
20 questions
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Lesson 3.7.1.2, Genetic crosses and inheritance patterns: 20 multiple choice questions for the AQA Biology (7402), Unit 7: Genetics, populations, evolution and ecosystems, written with Revision Ninja.
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The 20 questions
-
What is the expected phenotypic ratio in the F2 generation of a monohybrid cross with complete dominance?
- 9:3:3:1
- 1:1
- 1:2:1
- 3:1
-
What is the expected phenotypic ratio of a dihybrid cross between two heterozygotes with independent assortment and complete dominance?
- 1:2:1
- 3:1
- 9:7
- 9:3:3:1
-
What is a test cross?
- A cross between an individual of unknown genotype and a homozygous recessive individual
- A cross between two homozygous dominant individuals, whose offspring always show the recessive phenotype in every generation
- A cross between two heterozygous individuals, which shows the expected ratio and so confirms the genotype of both parents directly
- Self-fertilisation of a heterozygous individual, which is the only way to reveal the genotype of an organism in a single generation
-
Sex-linked genes are:
- Genes found only on chromosome 21
- Genes located on the X chromosome
- Genes located on mitochondrial DNA
- Genes located only on autosomes
-
What is the correct formula for the chi-squared statistic?
- Sum of (O - E) divided by E
- Sum of (O - E) squared multiplied by E
- Sum of (O + E) squared divided by E
- Sum of (O - E) squared divided by E
-
A chi-squared test compares four phenotypic classes. How many degrees of freedom are used?
- 4
- 2
- 3
- 5
-
Epistasis is best described as:
- Genes on the same chromosome being inherited together
- One gene masking or modifying the expression of a different gene
- A gene being switched off by methylation of its promoter
- Two alleles of the same gene both being fully expressed
-
What is the probability that a child of two heterozygous parents (Aa x Aa) will be aa?
- 1/2
- 1/4
- 3/4
- 1/16
-
In a cross Bb x bb, what is the expected genotypic ratio of the offspring?
- 3:1 B to b
- 9:3:3:1
- 1:2:1 BB to Bb to bb
- 1:1 Bb to bb
-
In a dihybrid cross AaBb x AaBb, what is the probability of an aabb offspring?
- 1/4
- 1/8
- 1/16
- 9/16
-
In a cross, 70 round and 30 wrinkled seeds are observed from 100 seeds. The expected ratio is 3:1. What is the chi-squared value?
- 1.33
- 0.25
- 5.00
- 2.67
-
A chi-squared value of 1.33 with 1 degree of freedom is compared with a critical value of 3.84 at p = 0.05. What is the correct conclusion?
- There is a significant difference, so the null hypothesis is rejected
- There is no significant difference, so the null hypothesis is accepted
- The expected ratio is disproved at p = 0.05
- The test cannot be concluded because the degrees of freedom are wrong
-
A woman who is a carrier of colour blindness (X^c X) has children with a normal man (X Y). What is the probability that a son is colour blind?
- 0
- 1/2
- 1
- 1/4
-
Two genes lie close together on the same chromosome. Why does a dihybrid test cross give fewer recombinant offspring than expected for independent assortment?
- The linked alleles tend to be inherited together, so recombination during meiosis is less frequent
- The linked alleles always segregate in a 9:7 ratio, because two linked genes always produce complementary gene action in the offspring
- The linked alleles are always lost during meiosis, so the offspring of the test cross never carry either allele of the two genes
- The genes are on different chromosomes so they cannot be inherited together, which means that independent assortment always applies to them
-
A dihybrid cross produces a 9:7 phenotypic ratio. Which genetic explanation fits best?
- Sex-linked inheritance of both genes, which means that both genes lie on the X chromosome and are passed on by the mother only
- Complementary gene action, where both dominant alleles are needed for one phenotype
- Codominance of both genes in every heterozygote, so each gene's two alleles are fully expressed and no allele is ever masked
- Linkage of the two genes on the same chromosome, which causes the two genes always to be inherited together with no recombination
-
A dihybrid cross of 160 offspring is expected to show the double dominant phenotype with 9:3:3:1 ratio. How many offspring should show this phenotype?
- 40
- 10
- 90
- 60
-
A chi-squared value of 8.20 is calculated with 3 degrees of freedom. The critical value at p = 0.05 is 7.82. What is the correct conclusion?
- The degrees of freedom must be recalculated, so no conclusion is possible
- The difference is not significant, so the expected ratio is confirmed
- The expected ratio is proven to be correct
- The difference is significant, so the expected ratio is rejected at p = 0.05
-
A colour-blind daughter has a sex-linked recessive condition. What must be true about her father?
- He must be a carrier but not colour blind
- He must be normal because the condition is never passed on by fathers
- He can be either normal or colour blind, with no effect on the daughter
- He must also be colour blind, since she receives an X chromosome from him
-
What phenotypic ratio is expected from a cross of two heterozygotes for a codominant gene?
- 1:1
- 3:1
- 9:3:3:1
- 1:2:1
-
Why do genes on the same chromosome give a non-Mendelian ratio in a dihybrid test cross?
- They tend to be inherited together, so recombinant offspring are produced less often than 50 per cent
- They are located on the Y chromosome, which is never inherited by offspring, so their alleles never appear in the test cross
- They produce more recombinant gametes than non-linked genes, so recombinant offspring are produced more often than 50 per cent
- They always assort independently, so the ratio is always 1:1:1:1 in every cross, whatever chromosomes the genes lie on
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