Lesson SH1-SH2

SH1-SH2 Confidence intervals for a mean from large samples Quiz: AQA Further Maths, Unit 4

20 questions

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Lesson SH1-SH2, Confidence intervals for a mean from large samples: 20 multiple choice questions for the AQA Further Maths (7367), Unit 4: Optional application 2: statistics, written with Revision Ninja.

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The 20 questions

  1. For a normal population with known variance sigma^2, which expression gives the symmetric 95% confidence interval for the population mean from a sample of n observations with mean xbar?

    • xbar ± 1.645 × sigma/sqrt(n)
    • xbar ± 1.96 × sigma^2/n
    • xbar ± 1.96 × sigma × sqrt(n)
    • xbar ± 1.96 × sigma/sqrt(n)
  2. What is the standard error of the sample mean for n independent observations from a population with standard deviation sigma?

    • sqrt(sigma/n)
    • sigma^2/sqrt(n)
    • sigma/n
    • sigma/sqrt(n)
  3. Which z value gives a symmetric 99% confidence interval for a normal mean, using the standard normal distribution?

    • 2.326
    • 1.645
    • 1.960
    • 2.576
  4. Which z value gives a symmetric 90% confidence interval for a normal mean?

    • 1.282
    • 2.576
    • 1.645
    • 1.960
  5. What does the confidence level of 95% mean for a symmetric confidence interval?

    • The sample mean lies inside the interval with probability 0.95 after each new sample is taken
    • There is a 95% probability that the true mean lies inside this particular calculated interval
    • About 95% of the individual data values lie inside the calculated interval
    • In repeated sampling, about 95% of intervals constructed this way would contain the true population mean
  6. A sample of n = 36 is taken from a normal population with known sigma = 6. The sample mean is 50. What is the 95% confidence interval for the population mean?

    • (48.04, 51.96)
    • (48.04, 52.96)
    • (49.00, 51.00)
    • (44.12, 55.88)
  7. A sample of n = 25 from a normal population with known sigma = 2 has mean 17.3. What is the symmetric 99% confidence interval for the population mean, to 2 decimal places?

    • (16.27, 18.33)
    • (15.97, 18.63)
    • (16.52, 18.08)
    • (17.30, 18.70)
  8. A sample of size n is multiplied by four, with sigma and the confidence level unchanged. How does the width of the symmetric confidence interval for the mean change?

    • It halves, because the width is proportional to 1/sqrt(n)
    • It is unchanged, because the width depends only on sigma and the confidence level
    • It quadruples, because the width is proportional to n
    • It doubles, because the width is proportional to sqrt(n)
  9. A normal population has known sigma = 4.5. What is the smallest sample size for a symmetric 95% confidence interval for the mean to have total width at most 2?

    • 39
    • 78
    • 156
    • 77
  10. A sample of n = 100 from a population with unknown variance has mean 24.6 and standard deviation 5.2. Using the large-sample method, what is the approximate symmetric 95% confidence interval for the mean?

    • (14.41, 34.79)
    • (23.26, 25.94)
    • (23.58, 25.62)
    • (24.08, 25.12)
  11. Why is the sample standard deviation s used in place of sigma when constructing a large-sample confidence interval for a mean?

    • The t-distribution must always be used instead of the normal distribution when sigma is unknown
    • s is always larger than sigma, so the interval it gives is wider and therefore safer
    • For large n, s is a good estimate of sigma, so the normal approximation with z values remains reasonable
    • The central limit theorem makes the sample standard deviation exactly equal to sigma for any sample
  12. A symmetric 95% confidence interval for a population mean is (12.1, 15.9). What is the sample mean used to construct it?

    • 14.0
    • 3.8
    • 15.9
    • 13.0
  13. A symmetric 95% confidence interval for a population mean is (12.1, 15.9). Assuming the z-based method, what is the standard error used?

    • Approximately 1.900
    • Approximately 0.950
    • Approximately 0.969
    • Approximately 3.724
  14. Keeping the data fixed, how does a symmetric 95% confidence interval for a mean change when the confidence level is raised to 99%?

    • It moves to a new centre, because the sample mean changes with the confidence level
    • It becomes wider, because the z value rises from 1.96 to 2.576
    • It becomes narrower, because the z value falls from 1.96 to 1.645
    • It is unchanged, because the same sample data are used
  15. A sample of n = 16 from a normal population with known sigma gives the 95% confidence interval (42.0, 48.0) for the mean. What is sigma, to 3 significant figures?

    • 3.06
    • 12.2
    • 1.53
    • 6.12
  16. A normal population has known sigma = 3. What is the smallest sample size needed for a symmetric 95% confidence interval for the mean to have margin of error at most 0.5?

    • 138
    • 277
    • 139
    • 35
  17. A symmetric 90% confidence interval is to be found for the mean of a normal population with known sigma = 10, using n = 25 observations with sample mean 60. What is the interval?

    • (56.08, 63.92)
    • (53.42, 66.58)
    • (58.00, 62.00)
    • (56.71, 63.29)
  18. Which statement about a symmetric 95% confidence interval is correct?

    • Before the sample is taken, there is a 95% probability that the random interval will contain the true population mean
    • After the sample is taken, there is a 95% probability that the true mean lies within this specific interval
    • The sample mean will lie inside the calculated interval for 95% of future samples
    • 95% of the individual observations in the sample lie inside the calculated interval
  19. A student has n = 12 normal observations with unknown variance. The student uses the sample standard deviation s in a z-based 95% interval. What is the best criticism of this method?

    • The z-based interval is too narrow, since the t-distribution with 11 degrees of freedom (critical value about 2.201) should be used
    • Using s always gives a narrower interval than using the unknown sigma would give
    • The critical value should be 2.576 because s is only a sample estimate of sigma
    • The z-based interval is valid because n = 12 is large enough for the central limit theorem to apply
  20. A sample of n = 400 from a population with unknown variance has mean 50 and standard deviation 8. What is the approximate symmetric 95% confidence interval for the mean?

    • (48.43, 51.57)
    • (49.61, 50.39)
    • (42.16, 57.84)
    • (49.22, 50.78)

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