Lesson SB5
SB5 Hypothesis test for a Poisson mean Quiz: AQA Further Maths, Unit 4
20 questions
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Lesson SB5, Hypothesis test for a Poisson mean: 20 multiple choice questions for the AQA Further Maths (7367), Unit 4: Optional application 2: statistics, written with Revision Ninja.
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The 20 questions
-
In a hypothesis test about a Poisson mean from a single observation, what is the null hypothesis typically?
- The parameter has the stated value, such as lambda = 4
- The variance is unknown
- The observation is always zero
- The alternative hypothesis is always true
-
What is the significance level of a test?
- The probability of accepting a false null hypothesis
- The sample mean
- The probability of rejecting the null hypothesis when it is true
- The power of the test
-
When a one-tailed test is carried out for a Poisson mean, what determines the critical region?
- The tail indicated by the alternative hypothesis
- The centre of the distribution
- The value of the observation alone
- Both tails, always equally
-
For a single observation X from Po(lambda) under H0, what quantity is compared with the significance level to decide whether to reject H0?
- The probability of a result at least as extreme as X, under H0
- The variance of X only
- The mean of X only
- The median of X only
-
A single observation X from Po(lambda) is used to test H0: lambda = 4 against H1: lambda < 4. P(X <= 1) for lambda = 4 is 0.0916 to 4 decimal places. At the 5% level, what is the conclusion if X = 1?
- Accept H1 with certainty
- Reject H0 since 0.0916 is less than 0.05
- Reject H0 since X = 1 is small
- Do not reject H0 since 0.0916 is greater than 0.05
-
A test of H0: lambda = 4 against H1: lambda < 4 at the 5% level observes X = 0. Taking P(X = 0) = e^(-4) = 0.0183, is H0 rejected?
- Yes, since 0.0183 is less than 0.05
- Yes, since 0.0183 is greater than 0.05
- No, since 0.0183 is greater than 0.05
- No, since X = 0 is not in the critical region
-
A single observation X from Po(5) is used to test H0: lambda = 5 against H1: lambda > 5. P(X >= 9) = 0.0681 and P(X >= 10) = 0.0318 to 4 decimal places. At the 5% level, what is the critical region?
- X >= 10
- X >= 11
- X >= 9
- X >= 8
-
A Poisson test of H0: lambda = 5 against H1: lambda > 5 observes X = 10. Using P(X >= 10) = 0.0318, what is the conclusion at the 5% level?
- Accept H0 as the mean is confirmed
- Reject H1 in favour of H0
- Reject H0 in favour of H1
- No conclusion can be drawn from one observation
-
Under H0: lambda = 5 for X ~ Po(5), what is P(X <= 0) to 4 decimal places?
- 0.0404
- 0.1755
- 0.0337
- 0.0067
-
Which statement best describes a Type I error in a Poisson test?
- Accepting H1 when it is false
- Rejecting H0 when it is true
- Accepting H0 when it is false
- Rejecting H1 when it is true
-
X ~ Po(lambda) under H0: lambda = 2 is tested against H1: lambda > 2 at the 5% level. For X = 6, P(X >= 6) = 0.0166 to 4 decimal places. What is the conclusion?
- Reject H0 since 0.0166 is greater than 0.05
- Reject H0 since 0.0166 is less than 0.05
- Accept H1 since the mean is 6
- Do not reject H0 since 6 is not large
-
A Poisson test uses H0: lambda = 3 against H1: lambda not equal to 3 (two-tailed). How does the method differ from a one-tailed test at the same significance level?
- Each tail is tested at the full significance level
- The critical region is always the upper tail only
- Each tail is tested at half the significance level
- The test uses a normal approximation with variance 3
-
A test of H0: lambda = 4 against H1: lambda < 4 at the 5% level has critical region X <= 0. What is the actual significance level?
- 5%
- 0.67%
- 9.16%
- 1.83%
-
A Poisson test has H0: lambda = 6 and H1: lambda < 6. P(X <= 2) = 0.0620 to 4 decimal places. Is X = 2 significant at the 5% level?
- No, since 0.0620 is greater than 0.05
- Yes, since 0.0620 is greater than 0.05
- No, since 0.0620 is less than 0.05
- Yes, since 0.0620 is less than 0.05
-
A test of H0: lambda = 5 against H1: lambda > 5 at the 5% level has critical region X >= 10. What is the probability of a Type I error?
- 0.0318
- 0.9682
- 0.05
- 0.0681
-
A Poisson test of H0: lambda = 2 against H1: lambda < 2 uses observation X = 0. P(X = 0) = e^(-2) = 0.1353. Is H0 rejected at the 5% level?
- Yes, since 0.1353 is greater than 0.05
- No, since 0.1353 is less than 0.05
- No, since 0.1353 is greater than 0.05
- Yes, since 0.1353 is less than 0.05
-
A Poisson test of H0: lambda = 3 against H1: lambda > 3 at the 5% level. For X = 7, P(X >= 7) = 0.0335 to 4 decimal places. What is the result?
- Accept H0 since 7 is near the mean
- No conclusion can be drawn
- Reject H0 in favour of H1
- Accept H1 with certainty
-
A Poisson test of H0: lambda = 4 against H1: lambda > 4 at the 5% level observes X = 8. P(X >= 8) = 0.0511 to 4 decimal places. What is the conclusion?
- Accept H1, since X = 8 exceeds the mean
- Reject H0, since 0.0511 is less than 0.05
- Do not reject H0, since 0.0511 is greater than 0.05
- Reject H0, since 8 is greater than 4
-
A Poisson test of H0: lambda = 10 against H1: lambda < 10 observes X = 3, with P(X <= 3) = 0.0103 to 4 decimal places. At the 5% level, is the result significant?
- Yes, since 0.0103 is less than 0.05
- Yes, since 0.0103 is greater than 0.05
- No, since 0.0103 is less than 0.05 only at the 1% level
- No, since 0.0103 is greater than 0.05
-
A two-tailed Poisson test of H0: lambda = 5 against H1: lambda not equal to 5 is carried out at the 5% level, so each tail has probability at most 0.025. What is the upper critical region?
- X >= 10
- X >= 9
- X >= 11
- X >= 12
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