Lesson G3
G3 Area enclosed by a polar curve Quiz: AQA Further Maths, Unit 2
20 questions
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Lesson G3, Area enclosed by a polar curve: 20 multiple choice questions for the AQA Further Maths (7367), Unit 2: Compulsory content, written with Revision Ninja.
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The 20 questions
-
The area enclosed by a polar curve r = f(theta) between theta = a and theta = b is given by which formula?
- integral from a to b of r d(theta)
- (1/2) integral from a to b of r d(theta)
- (1/2) integral from a to b of r^2 d(theta)
- integral from a to b of r^2 d(theta)
-
What is the area enclosed by the circle r = a?
- pi a^2
- pi a^2/2
- 2 pi a^2
- pi a
-
Find the area enclosed by r = 2 for 0 <= theta <= pi/2.
- pi/2
- 2 pi
- 4 pi
- pi
-
What is the area enclosed by the full cardioid r = 1 + cos(theta)?
- pi
- 3 pi
- 3 pi/2
- 2 pi
-
What is the area enclosed by the full curve r = 2 cos(theta)?
- 2 pi
- pi/2
- pi
- 4 pi
-
Find the area enclosed by r = 3 for 0 <= theta <= pi/3.
- 3 pi
- pi/2
- 3 pi/2
- 9 pi/2
-
What is the area of one petal of the rose r = sin(2 theta)?
- pi/8
- pi/4
- pi/2
- pi/16
-
What is the area enclosed by the full curve r = 2(1 - cos(theta))?
- 6 pi
- 2 pi
- 12 pi
- 3 pi
-
Find the area enclosed by the full curve r = 4 sin(theta).
- 2 pi
- pi
- 8 pi
- 4 pi
-
Which integral gives the area enclosed by the full curve r = 2 + cos(theta)?
- (1/2) integral from 0 to 2 pi of (2 + cos(theta))^2 d(theta)
- (1/2) integral from 0 to 2 pi of (2 + cos^2(theta)) d(theta)
- integral from 0 to 2 pi of (2 + cos(theta))^2 d(theta)
- (1/2) integral from 0 to 2 pi of (2 + cos(theta)) d(theta)
-
Why is the polar area element (1/2) r^2 d(theta) rather than r d(theta)?
- Because theta is measured in degrees
- Because area is always linear in r
- Because r is always equal to 1 on any curve
- A thin sector has area approximately (1/2) r^2 d(theta), which is quadratic in r
-
Which limits of theta give one complete traversal of the circle r = a?
- 0 to pi/2
- -pi/2 to pi/2
- 0 to pi
- 0 to 2 pi
-
Find the area enclosed by r = 3 sin(theta).
- 9 pi/4
- 3 pi/4
- 9 pi/2
- 3 pi
-
Find the area enclosed by r = 1 + cos(theta) for 0 <= theta <= pi.
- 3 pi/2
- pi/2
- pi
- 3 pi/4
-
Find the area enclosed by r = 4 for 0 <= theta <= pi.
- 2 pi
- 4 pi
- 8 pi
- 16 pi
-
Find the area enclosed by r = 2 for pi/4 <= theta <= pi/2.
- pi
- pi/2
- pi/4
- 2 pi
-
Find the area of the region between the curves r = 2 and r = 4 for 0 <= theta <= pi/2.
- 3 pi
- 6 pi
- 12 pi
- pi
-
Find the area enclosed by r = 2 sin(theta) for pi/6 <= theta <= pi/2.
- 2 pi/3 + sqrt(3)/2
- pi/3 + sqrt(3)/4
- pi/6 + sqrt(3)/8
- pi/3 - sqrt(3)/4
-
A sector of the circle r = 5 spans theta from 0 to 2 radians. What is its area?
- 5
- 12.5
- 50
- 25
-
What is the area enclosed by one loop of the curve r = cos(3 theta)?
- pi/24
- pi/12
- pi/4
- pi/6
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