Lesson R6
R6 Friction and limiting equilibrium Quiz: AQA Maths, Unit 12
20 questions
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Lesson R6, Friction and limiting equilibrium: 20 multiple choice questions for the AQA Maths (7357), Unit 12: Mechanics, written with Revision Ninja.
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The 20 questions
-
The friction model F <= mu R means:
- Friction does not depend on the normal reaction
- Friction is always greater than the normal reaction
- Friction can be at most mu times the normal reaction
- Friction is always mu times the weight
-
The coefficient of friction is:
- The product of friction and the normal reaction
- The ratio of weight to friction
- The ratio of limiting friction to the normal reaction
- The friction force per unit mass
-
Limiting friction occurs when:
- The body is at rest with no forces acting
- Friction is greater than the applied force
- The body is on the point of sliding and F = mu R
- The friction force is zero
-
A body on a horizontal surface has no other vertical forces. What is the normal reaction R?
- 2mg
- F
- Zero
- mg
-
In which direction does friction act on a body?
- In the direction of the applied force always
- In the direction of gravity
- Opposite to the direction of actual or intended relative motion
- Perpendicular to the surface
-
A 5 kg block rests on a rough horizontal floor with mu = 0.4, and g = 10 m s^-2. What is the limiting friction?
- 0.4 N
- 50 N
- 20 N
- 125 N
-
A 10 kg crate on a rough floor with mu = 0.3 is pulled horizontally by 20 N from rest, with g = 10 m s^-2. What happens?
- Friction is zero and the crate stays at rest
- Friction is 20 N and the crate moves
- Friction is 20 N and the crate stays at rest
- Friction is 30 N and the crate moves
-
The same crate (10 kg, mu = 0.3, g = 10 m s^-2) is pulled horizontally by 40 N. What is its acceleration?
- 0 m s^-2
- 3 m s^-2
- 4 m s^-2
- 1 m s^-2
-
A 4 kg body rests on a rough plane inclined at 30 degrees, with g = 10 m s^-2. What is the normal reaction?
- 34.6 N
- 40.0 N
- 23.1 N
- 20.0 N
-
A 40 N block rests on a rough slope, with a tangential component of weight 20 N down the slope and maximum friction 12 N. What happens?
- It stays in equilibrium because friction exceeds weight
- It stays at rest, since 12 N exceeds 20 N
- It slides, since 20 N exceeds the limiting friction of 12 N
- It stays at rest, since friction of 20 N holds it
-
A body is on the point of sliding down a rough plane. Which relationship holds for the angle theta of the plane?
- sin(theta) = mu
- cos(theta) = mu
- tan(theta) = mu
- mu = theta
-
A 5 kg block on a rough horizontal plane with mu = 0.2 is pulled by 15 N at 30 degrees above the horizontal, with g = 10 m s^-2. What is the friction force, to 1 decimal place?
- 3.0 N
- 10.0 N
- 8.5 N
- 4.0 N
-
For the block in the previous question (5 kg, mu = 0.2, pulled by 15 N at 30 degrees, g = 10 m s^-2), what is the acceleration, to 2 decimal places?
- 0.20 m s^-2
- 1.50 m s^-2
- 0.90 m s^-2
- 2.60 m s^-2
-
A 6 kg body slides at constant velocity on a rough horizontal surface with mu = 0.25, with g = 10 m s^-2. What horizontal force is applied?
- 15 N
- 60 N
- 6 N
- 24 N
-
A 4 kg body slides down a rough plane inclined at 30 degrees with mu = 0.2, g = 10 m s^-2. What is its acceleration, to 1 decimal place?
- 5.0 m s^-2
- 3.3 m s^-2
- 4.3 m s^-2
- 1.7 m s^-2
-
A body rests in equilibrium on a rough plane with mu = 0.6. What is the largest angle with the horizontal before it slips, to 1 decimal place?
- 59.0 degrees
- 16.7 degrees
- 45.0 degrees
- 31.0 degrees
-
A body on the point of sliding has friction 12 N and normal reaction 30 N. What is the coefficient of friction?
- 0.25
- 0.6
- 2.5
- 0.4
-
A 5 kg block on a rough table with mu = 0.2 is connected by a light string over a smooth pulley to a hanging 3 kg mass, with g = 10 m s^-2. What is the acceleration?
- 1.5 m s^-2
- 0.25 m s^-2
- 3.0 m s^-2
- 2.5 m s^-2
-
For the system in the previous question (5 kg block with mu = 0.2 and 3 kg hanging, g = 10 m s^-2), what is the tension in the string?
- 22.5 N
- 7.5 N
- 15 N
- 30 N
-
A body of weight 10 N rests on a rough horizontal surface with mu = 0.3. A horizontal force of 2 N is applied. Which statement is correct?
- It slides, since friction is zero
- It is in equilibrium, with friction of 2 N since 2 N is less than the limiting value 3 N
- It is in equilibrium, with friction of 3 N
- It slides, since 2 N is less than its weight
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