Lesson Q1-Q2
Q1-Q2 Kinematics language and graphs Quiz: AQA Maths, Unit 12
20 questions
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Lesson Q1-Q2, Kinematics language and graphs: 20 multiple choice questions for the AQA Maths (7357), Unit 12: Mechanics, written with Revision Ninja.
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The 20 questions
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Displacement is best described as:
- A scalar giving the total path length
- A vector giving the change in position, including direction
- The total distance travelled, always positive
- The rate of change of velocity
-
Distance travelled is:
- A vector from the start point to the end point
- Always zero for a round trip
- The rate at which position changes
- A scalar giving the total length of the path followed
-
Speed is best described as:
- The rate of change of velocity
- The change in displacement
- A vector with direction
- The magnitude of velocity, which is a scalar
-
A velocity-time graph has a horizontal line at 5 m s^-1 for 8 s. What is the acceleration during this time?
- 40 m s^-2
- 8 m s^-2
- 0 m s^-2
- 5 m s^-2
-
Acceleration is best described as:
- The total distance covered per unit time
- The rate of change of displacement
- The change in velocity over the displacement
- The rate of change of velocity
-
A particle moves 3 m east and then 4 m west. What is its displacement from the start?
- 7 m east
- 7 m west
- 1 m east
- 1 m west
-
The particle in the previous situation moves 3 m east and then 4 m west. What is the total distance travelled?
- 3 m
- 7 m
- 1 m
- 5 m
-
On a velocity-time graph, what does the gradient represent?
- Velocity
- Acceleration
- Displacement
- Distance
-
On a velocity-time graph, what does the area between the graph and the time axis represent?
- Acceleration
- Time
- Displacement, with areas below the axis counted as negative
- Average speed only
-
On a displacement-time graph, what does the gradient represent?
- Speed squared
- Velocity
- Acceleration
- Displacement
-
A horizontal line on a displacement-time graph shows that the object is:
- Moving with constant speed in reverse
- At rest
- Moving with constant acceleration
- Moving with constant positive velocity
-
A straight line with positive gradient on a displacement-time graph shows:
- Constant positive velocity
- Constant acceleration
- Constant negative velocity
- Increasing velocity
-
A velocity-time graph goes from 0 to 12 m s^-1 in 4 s, then stays at 12 m s^-1 for 6 s. What is the displacement over the 10 s?
- 120 m
- 24 m
- 72 m
- 96 m
-
The same velocity-time graph rises from 0 to 12 m s^-1 in 4 s. What is the acceleration during these 4 s?
- 3 m s^-2
- 0 m s^-2
- 12 m s^-2
- 48 m s^-2
-
A displacement-time graph passes through (0, 0), (4, 20), (6, 20) and (10, 0), with straight lines between points. What is the velocity between 0 and 4 s?
- 0 m s^-1
- -5 m s^-1
- 20 m s^-1
- 5 m s^-1
-
For the displacement-time graph through (0, 0), (4, 20), (6, 20) and (10, 0), what is the average speed over 0 to 10 s?
- 2 m s^-1
- 20 m s^-1
- 4 m s^-1
- 0 m s^-1
-
A velocity-time graph shows velocity changing uniformly from +6 m s^-1 to -6 m s^-1 in 4 s. What is the acceleration?
- 0 m s^-2
- -6 m s^-2
- 3 m s^-2
- -3 m s^-2
-
A particle moves at -4 m s^-1 for 2 s on a velocity-time graph. What is its contribution to displacement?
- 0 m
- -8 m
- -2 m
- 8 m
-
A velocity-time graph has area 30 m above the time axis and area 10 m below it. What are the displacement and distance?
- Displacement 0 m and distance 40 m
- Displacement 40 m and distance 20 m
- Displacement 20 m and distance 40 m
- Displacement 20 m and distance 20 m
-
The gradient of a displacement-time curve falls steadily to zero at t = 5 s. What does this mean?
- The acceleration is constant at t = 5 s
- The velocity decreases to zero at t = 5 s
- The velocity reaches a maximum at t = 5 s
- The displacement is zero at t = 5 s
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