Lesson H8
H8 Interpreting solutions of differential equations Quiz: AQA Maths, Unit 8
20 questions
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Lesson H8, Interpreting solutions of differential equations: 20 multiple choice questions for the AQA Maths (7357), Unit 8: Integration, written with Revision Ninja.
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The 20 questions
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A population model P = kP with k > 0 predicts unlimited growth. What is a limitation of this model?
- It ignores limited resources, so it predicts unrealistic growth for large t
- It predicts that the population always declines
- It predicts no change over time
- It predicts a population of zero at all times
-
For dv/dt = 9.8 - 0.2v, what does the terminal velocity represent?
- The constant velocity reached when the acceleration is zero
- The maximum acceleration of the object
- The initial velocity of the object
- The velocity at time t = 0
-
For dP/dt = kP with k > 0, what does the model predict as t tends to infinity?
- P grows without bound
- P oscillates between two values
- P tends to a fixed limit
- P tends to zero
-
What does a particular solution of a differential equation describe?
- A family of curves with no constraints
- The limit of the solution as x tends to infinity
- A single curve that satisfies the given starting condition
- The rate of change only
-
In kinematics, what does a negative velocity indicate?
- The particle is at rest
- The particle has negative mass
- The particle moves in the negative direction
- The particle has zero displacement
-
What is a limitation of a mathematical model in general?
- A value that can never be calculated
- An error in the mathematical working
- A result that always matches the data
- An assumption that may not hold in the real situation
-
For s = 4t - t^2 metres, at what time does the particle momentarily stop?
- t = 0 s
- t = 2 s
- t = 4 s
- t = 1 s
-
The model dv/dt = 9.8 - 0.2v assumes a constant resistance coefficient. Which is a limitation?
- It predicts the object speeds up forever
- It predicts a negative terminal velocity
- The coefficient 0.2 may not hold at high speeds or in changing air density
- It ignores gravity entirely
-
A demand model Q = 200e^(-0.4p) is used for prices p. Which is a sensible interpretation and limitation?
- Demand is always positive and never exactly zero, which may be unrealistic at very high prices
- Demand is negative for every positive price
- Demand stays at 200 for all prices
- Demand is zero at price zero
-
For dP/dt = 0.05P, what is the doubling time of the population, to 1 decimal place?
- 20 years
- 13.9 years
- 7 years
- 0.05 years
-
A particle satisfies v = 49(1 - e^(-0.2t)) m/s. What is its velocity at t = 10 s, to 1 decimal place?
- 49 m/s
- 21.6 m/s
- 42.4 m/s
- 9.8 m/s
-
The population model P = 500e^(0.02t) gives P at t = 100. Which value is the model's prediction, to the nearest whole number?
- 3695
- 10000
- 1000
- 500
-
A particle has displacement s = 2t^3 - 9t^2 + 12t. At which times does it change direction?
- t = 1 s only
- t = 0 s and t = 3 s
- t = 2 s and t = 4 s
- t = 1 s and t = 2 s
-
A particle has velocity v = 10 - 2t. At what time does it come to rest?
- 2 s
- 10 s
- 5 s
- 2.5 s
-
A particle is projected with velocity 60 m/s under dv/dt = 9.8 - 0.2v. What happens to its velocity?
- It decreases to zero
- It decreases towards 49 m/s
- It increases without bound
- It stays at 60 m/s
-
Which change makes the population model dP/dt = kP more realistic for large populations?
- Add a term that slows growth as P approaches a limit such as a carrying capacity
- Set k to zero
- Use dP/dt = kt instead
- Replace k with a negative constant
-
For dv/dt = 9.8 - 0.2v with v = 0 at t = 0, how long does it take to reach 90% of terminal velocity, to 1 decimal place?
- 9.8 s
- 11.5 s
- 22.0 s
- 4.5 s
-
For s = 4t - t^2, what is the average velocity over 0 <= t <= 4?
- -2 m/s
- 2 m/s
- 0 m/s
- 4 m/s
-
A velocity model v = 49(1 - e^(-0.2t)) m/s is used for large t. What value does the velocity approach?
- 49 m/s
- 0 m/s
- 9.8 m/s
- There is no limiting value
-
For a particle with displacement s = 2t^2 - 8t metres, what is the displacement at t = 2 s?
- 8 m
- 0 m
- -8 m
- -16 m
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