Lesson B6
B6 Polynomials, algebraic division and the factor theorem Quiz: AQA Maths, Unit 2
20 questions
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Lesson B6, Polynomials, algebraic division and the factor theorem: 20 multiple choice questions for the AQA Maths (7357), Unit 2: Algebra and functions, written with Revision Ninja.
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The 20 questions
-
Expand (2x - 1)(x + 4).
- 2x^2 + 9x - 4
- 2x^2 + 7x + 4
- 2x^2 - 7x - 4
- 2x^2 + 7x - 4
-
What does the factor theorem state?
- If f(a) = 0 then (x - a) is a factor of f(x)
- If (x - a) is a factor then f(a) = a
- If f(a) = 1 then (x - a) is a factor of f(x)
- If f(-a) = 0 then (x - a) is a factor of f(x)
-
What is the remainder when a polynomial f(x) is divided by (x - a)?
- f(a)
- a f(0)
- f'(a)
- f(-a)
-
Factorise x^3 - 6x^2 + 11x - 6 fully.
- (x - 1)(x - 2)(x - 3)
- (x - 1)(x + 2)(x - 3)
- (x - 1)(x - 2)(x + 3)
- (x + 1)(x + 2)(x + 3)
-
Which of these is a factor of x^3 + 2x^2 - x - 2?
- (x^2 + 2)
- (x - 2)
- (x + 3)
- (x + 2)
-
What is the remainder when x^3 + 2x^2 - 5 is divided by (x - 2)?
- 11
- 16
- 3
- -5
-
For what value of k is (x - 2) a factor of x^3 - kx + 6?
- k = 5
- k = 14
- k = -7
- k = 7
-
Divide 2x^3 + 3x^2 - 5x + 1 by (x + 2). What are the quotient and remainder?
- Quotient 2x^2 - 3x + 1, remainder 7
- Quotient 2x^2 - x - 3, remainder 7
- Quotient 2x^2 - x - 3, remainder -7
- Quotient 2x^2 + x - 3, remainder 7
-
Simplify (x^2 - 9)/(x^2 + x - 6).
- (x + 3)/(x - 2)
- (x - 3)/(x - 2)
- (x - 3)/(x + 2)
- (x - 3)(x + 2)
-
Which expression is NOT a polynomial?
- x^2 - 3
- 3x^3 + 1
- 1/x + 2
- x^4 - x
-
Find a and b so that x^3 + ax^2 + bx - 6 has both (x - 1) and (x - 2) as factors.
- a = -6, b = 11
- a = 5, b = 0
- a = 6, b = -1
- a = -6, b = -11
-
Simplify (x^3 - 1)/(x - 1) for x not equal to 1.
- x^2 + x - 1
- x^2 - x + 1
- x^2 + x + 1
- x^2 + 1
-
What is the coefficient of x^2 in the expansion of (x + 3)(x^2 - 2x + 1)?
- 3
- -5
- 1
- -2
-
Simplify 3a^2b - 2ab^2 + 5a^2b + ab^2.
- 6a^2b - ab^2
- 8a^2b - 3ab^2
- 8a^2b - ab^2
- 8a^2b + ab^2
-
Factorise 8x^3 - 27 fully.
- (2x - 3)(4x^2 + 6x + 9)
- (2x + 3)(4x^2 - 6x + 9)
- (2x - 3)(4x^2 - 6x + 9)
- (2x - 3)(4x^2 + 6x - 9)
-
For f(x) = x^3 - 4x^2 + kx + 6, the remainder is zero when divided by (x + 1). What is k?
- k = 11
- k = 1
- k = -1
- k = 5
-
Factorise x^3 - 7x + 6 fully.
- (x - 1)(x + 2)(x + 3)
- (x - 1)(x - 2)(x + 3)
- (x - 1)(x - 2)(x - 3)
- (x + 1)(x - 2)(x - 3)
-
What is the remainder when x^4 + 1 is divided by (x + 1)?
- 1
- 2
- -2
- 0
-
What is the degree of the remainder when a polynomial is divided by a linear divisor?
- Equal to the degree of the quotient
- Zero, so the remainder is a constant
- Equal to the degree of the dividend
- One, so the remainder is linear
-
Given that (x + 2) is a factor of x^3 + kx^2 - 4x + 4, find k.
- k = 1
- k = -3
- k = -1
- k = 3
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