Lesson 5.2.2

5.2.2 Reacting gas volumes and solution concentrations Quiz: Pearson Edexcel Chemistry, Unit 5

20 questions

Written by Revision Ninja · Last reviewed 11 October 2026

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Lesson 5.2.2, Reacting gas volumes and solution concentrations: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 5: Formulae, Equations and Amounts of Substance, written with Revision Ninja.

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The 20 questions

  1. What is the approximate molar volume of a gas at room temperature and pressure?

    • 24 dm3 mol-1
    • 1.00 dm3 mol-1
    • 22.4 dm3 mol-1
    • 6.02 dm3 mol-1

  2. What volume does 0.5 mol of carbon dioxide occupy at room temperature and pressure?

    • 24 dm3
    • 48 dm3
    • 6 dm3
    • 12 dm3

  3. What volume of carbon dioxide forms when 10 g of calcium carbonate reacts fully with acid? (Molar volume 24 dm3 mol-1)

    • 1.0 dm3
    • 4.4 dm3
    • 2.4 dm3
    • 24 dm3

  4. What is the concentration of a solution made by dissolving 0.25 mol of solute in 500 cm3?

    • 0.05 mol dm-3
    • 0.50 mol dm-3
    • 2.0 mol dm-3
    • 0.125 mol dm-3

  5. How many dm3 are in 350 cm3?

    • 35.0 dm3
    • 0.0350 dm3
    • 3.50 dm3
    • 0.350 dm3

  6. What is the concentration in g dm-3 of a 0.5 mol dm-3 sodium chloride solution? (NaCl = 58.5)

    • 117 g dm-3
    • 58.5 g dm-3
    • 14.6 g dm-3
    • 29.3 g dm-3

  7. How many moles of sodium hydroxide are in 25.0 cm3 of 0.200 mol dm-3 NaOH solution?

    • 0.125 mol
    • 0.00500 mol
    • 0.00200 mol
    • 0.0500 mol

  8. 25.0 cm3 of 0.100 mol dm-3 HCl neutralises 20.0 cm3 of NaOH solution. What is the NaOH concentration?

    • 0.250 mol dm-3
    • 0.100 mol dm-3
    • 0.0800 mol dm-3
    • 0.125 mol dm-3

  9. 10 cm3 of hydrogen reacts with oxygen in 2H2 + O2 -> 2H2O. What volume of oxygen is needed at the same conditions?

    • 20 cm3
    • 10 cm3
    • 5 cm3
    • 2.5 cm3

  10. What volume of oxygen is needed to burn 50 cm3 of methane, CH4 + 2O2 -> CO2 + 2H2O?

    • 200 cm3
    • 100 cm3
    • 25 cm3
    • 50 cm3

  11. Which indicator changes from pink to colourless at the end point of a NaOH into HCl titration?

    • Phenolphthalein
    • Universal indicator
    • Methyl orange
    • Litmus

  12. What is the concentration of a solution made from 4.0 g of NaOH in 250 cm3? (NaOH = 40)

    • 0.40 mol dm-3
    • 0.10 mol dm-3
    • 1.0 mol dm-3
    • 4.0 mol dm-3

  13. How many moles of HCl are in 100 cm3 of 2.0 mol dm-3 hydrochloric acid?

    • 0.20 mol
    • 0.02 mol
    • 0.50 mol
    • 2.0 mol

  14. What volume of hydrogen forms at room temperature and pressure from 0.25 mol of zinc with excess acid?

    • 12 dm3
    • 3.0 dm3
    • 24 dm3
    • 6.0 dm3

  15. What volume of oxygen is needed to burn 30 cm3 of propane, C3H8 + 5O2 -> 3CO2 + 4H2O?

    • 60 cm3, which would be the volume needed if the reaction used two volumes of oxygen for each volume of propane
    • 75 cm3, which would be the volume needed if the reaction used two and a half volumes of oxygen per propane
    • 150 cm3
    • 30 cm3, which would be the volume needed if the reaction used one volume of oxygen for each volume of propane

  16. A 0.200 mol dm-3 solution of Na2CO3 is made. How many moles of Na+ ions are in 50.0 cm3?

    • 0.200 mol
    • 0.0100 mol
    • 0.0200 mol
    • 0.0400 mol

  17. Why is a standard solution prepared in a volumetric flask?

    • The flask is cheaper than a beaker, which makes it the most economical choice for preparing solutions in the lab
    • The flask makes the solution more reactive, so the reaction with the sample is completed more quickly overall
    • The flask holds a precisely known volume, so the concentration of the solution can be calculated accurately
    • The flask prevents any reaction with the solvent, which keeps the solution pure for the whole of the titration

  18. What volume of 0.100 mol dm-3 HCl is needed to neutralise 0.0050 mol of NaOH?

    • 5 cm3
    • 50 cm3
    • 500 cm3
    • 25 cm3

  19. Three concordant titres are 24.10, 24.00 and 24.05 cm3. What is the mean titre?

    • 24.10 cm3
    • 24.05 cm3
    • 24.00 cm3
    • 24.20 cm3

  20. Why must a titration be repeated?

    • To remove the need for a burette, since the repeated readings can be taken from a pipette instead
    • To obtain concordant titres and reduce the effect of random error
    • To make the indicator change colour more strongly, so that the end point is easier to see with the eye
    • To increase the concentration of the solution in the flask, which reduces the volume needed for the titration

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