Lesson 1.3.2
1.3.2 Electronic configurations and s, p, d blocks Quiz: Pearson Edexcel Chemistry, Unit 1
20 questions
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Lesson 1.3.2, Electronic configurations and s, p, d blocks: 20 multiple choice questions for the Pearson Edexcel Chemistry (9CH0), Unit 1: Atomic Structure and the Periodic Table, written with Revision Ninja.
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The 20 questions
-
What is the electronic configuration of a neutral sodium atom?
- 1s2 2s2 2p6 3s1
- 1s2 2s2 2p6 3s2
- 1s2 2s2 2p5 3s2
- 1s2 2s2 2p6 3p1
-
The electronic configuration of an element is [Ar] 3d10 4s2 4p3. Which block does it belong to?
- f-block
- p-block
- s-block
- d-block
-
Which ion has the same electron configuration as argon?
- Al
- Mg2+
- Na+
- Cl-
-
Which electronic configuration is correct for a chromium atom (Z = 24)?
- 1s2 2s2 2p6 3s2 3p6 3d4 4s2
- 1s2 2s2 2p6 3s2 3p6 3d6
- 1s2 2s2 2p6 3s2 3p6 4s2 4p4
- 1s2 2s2 2p6 3s2 3p6 3d5 4s1
-
What is the electronic configuration of the Fe3+ ion? (Fe has Z = 26.)
- [Ar] 4s1 3d4
- [Ar] 3d6
- [Ar] 3d3
- [Ar] 3d5
-
Which block of the periodic table contains elements whose highest-energy electron is in an s sub-shell?
- p-block
- s-block
- f-block
- d-block
-
How many unpaired electrons does an oxygen atom have? (Configuration 1s2 2s2 2p4.)
- 2
- 4
- 0
- 6
-
Which diagram shows the correct electrons-in-boxes notation for nitrogen's 2p3 sub-shell?
- Three boxes, two of which contain paired arrows
- Three boxes, each containing one arrow
- Two boxes each containing two arrows and one empty box
- One box containing three arrows
-
Which element has the electronic configuration [Ne] 3s2 3p3?
- Nitrogen, which has a 2p3 configuration with three unpaired electrons in its outer shell of the atom
- Aluminium, which has a 3s2 3p1 configuration with one unpaired electron in its outer shell of the atom
- Phosphorus
- Sulfur, which has a 3s2 3p4 configuration with two unpaired electrons in its outer shell of the atom
-
What is the block of an element with configuration [Ar] 3d2 4s2?
- p-block
- f-block
- d-block
- s-block
-
How many electrons are in the 3d sub-shell of a Mn2+ ion? (Mn has Z = 25.)
- 3
- 7
- 2
- 5
-
A neutral atom has electronic configuration 1s2 2s2 2p6 3s2 3p3. What is its atomic number and identity?
- 13, aluminium, which is a metal with three electrons in its outer shell and a 3p1 configuration
- 14, silicon, which is a giant covalent element with four electrons in its outer shell of the atom
- 16, sulfur, which is a simple molecular element with six electrons in its outer shell of the atom
- 15, phosphorus
-
Explain why Zn2+ is not regarded as a transition metal ion.
- Zn2+ is [Ar] 4s2, so it has no d electrons at all and cannot be classed as a transition metal ion
- Zn2+ is [Ar] 3d10 4s2, which contains a full 4s sub-shell and an incomplete d sub-shell in the same ion
- Zn2+ is [Ar] 3d10, so it has a full d sub-shell rather than an incomplete one
- Zn2+ is [Ar] 3d8, so it has an incomplete d sub-shell and therefore counts as a transition metal ion
-
Explain why vanadium(II) ion has configuration [Ar] 3d3.
- Vanadium loses one 4s and one 3d electron to form V2+, leaving the remaining electrons in a 3d3 4s1 pattern
- Vanadium is [Ar] 3d3 4s2, and both 4s electrons are lost first to form V2+
- Vanadium gains two electrons into the 3d sub-shell, which partly fills it and leaves the 4s2 pair unchanged
- Vanadium loses 3d electrons first, so the 4s2 electrons remain in the ion and it gains extra stability
-
Why does a Cu+ ion have configuration [Ar] 3d10?
- Copper's 3d sub-shell is always full in every ion, so the Cu+ ion has exactly the same configuration as copper
- Copper's configuration is [Ar] 3d10 4s1, so losing the single 4s electron leaves a full 3d sub-shell
- Copper gains an electron into its 3d sub-shell when it forms the Cu+ ion, which completes the sub-shell
- Copper's configuration is [Ar] 3d9 4s2, so losing one 3d electron leaves a full 3d sub-shell in the ion
-
A student gives the configuration of Fe2+ as [Ar] 3d4 4s2. Which statement identifies the error?
- Fe2+ should have lost 3d electrons only, so the configuration [Ar] 3d4 4s2 shown by the student is correct as written
- Fe2+ is [Ar] 3d6, because the two 4s electrons are lost and the 3d count stays at six
- Fe2+ is [Ar] 4s2 3d5, because 3d electrons are always lost before the 4s electrons in any ion of iron
- Fe2+ should be [Ar] 3d8, since ions gain electrons from the solvent and so add them to the 3d sub-shell
-
Which statement correctly explains how the s, p and d blocks are defined?
- A block is set by the sub-shell that the last electron enters
- A block is set by the number of protons in the nucleus, which determines which sub-shell type the atom fills
- A block is set by the shell number of the outermost electron, regardless of which sub-shell it occupies
- A block is set by the number of valence electrons alone, without any reference to the sub-shell being filled
-
Which electronic configuration corresponds to the Ca2+ ion? (Ca has Z = 20.)
- 1s2 2s2 2p6 3s2 3p4
- 1s2 2s2 2p6 3s2 3p6 3d2
- 1s2 2s2 2p6 3s2 3p6 4s2
- 1s2 2s2 2p6 3s2 3p6
-
Which atom has the electronic configuration 1s2 2s2 2p6 3s2 3p4?
- Phosphorus
- Sulfur
- Selenium
- Oxygen
-
How many unpaired electrons does a ground-state chromium atom have?
- 0
- 4
- 6
- 2
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