Lesson 3.02h
3.02h Motion under gravity Quiz: OCR Maths, Unit 17
20 questions
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Lesson 3.02h, Motion under gravity: 20 multiple choice questions for the OCR Maths (H240), Unit 17: Kinematics, written with Revision Ninja.
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The 20 questions
-
What standard value of g is used in OCR A Level Mathematics?
- 9.81 m s⁻²
- 9.8 m s⁻²
- 10 m s⁻²
- 9.78 m s⁻²
-
In vector notation using unit vectors i and j, what is acceleration under gravity?
- g j
- g i
- -g j
- -g i
-
Which assumption is made when modelling a projectile as a particle?
- Variable shape
- Variable mass
- Ignore gravity
- Ignore rotational effects
-
What is the horizontal acceleration of a projectile when ignoring air resistance?
- 9.8 m s⁻²
- -9.8 m s⁻²
- Zero
- Variable
-
What is the vertical component of velocity at the highest point of a trajectory?
- Zero
- Maximum
- -9.8 m s⁻¹
- Initial velocity
-
What is the mathematical shape of a projectile trajectory under constant gravity?
- Hyperbola
- Parabola
- Circle
- Ellipse
-
How does including air resistance affect the maximum height reached by a projectile?
- Increases it
- Decreases it
- Doubles it
- No effect
-
In the cartesian equation of a projectile trajectory, what does the variable y represent?
- Time of flight
- Horizontal distance
- Total distance
- Vertical displacement
-
A ball is thrown vertically upwards at 19.6 m s⁻¹. How long to reach max height?
- 1 second
- 9.8 seconds
- 2 seconds
- 4 seconds
-
A particle is projected with initial velocity vector (3i + 4j) m s⁻¹. What is its initial speed?
- 5 m s⁻¹
- 7 m s⁻¹
- 12 m s⁻¹
- 1 m s⁻¹
-
What is the horizontal component of initial velocity for a launch speed u at angle θ?
- u g
- u cos θ
- u tan θ
- u sin θ
-
What is the vertical component of initial velocity for a launch speed u at angle θ?
- u sin θ
- u tan θ
- u cos θ
- u g
-
A stone is dropped from rest. What is its speed after 3 seconds under gravity?
- 44.1 m s⁻¹
- 29.4 m s⁻¹
- 9.8 m s⁻¹
- 19.6 m s⁻¹
-
A particle is projected horizontally at 10 m s⁻¹. What is its horizontal speed after 2 seconds?
- 19.6 m s⁻¹
- 0 m s⁻¹
- 29.6 m s⁻¹
- 10 m s⁻¹
-
What expression gives the time taken for a projectile to reach its maximum height?
- (u sin θ) / 2g
- u / g
- (u cos θ) / g
- (u sin θ) / g
-
A ball is thrown vertically upwards at 9.8 m s⁻¹. What maximum height does it reach?
- 19.6 metres
- 9.8 metres
- 2.45 metres
- 4.9 metres
-
For a projectile launched from the origin, what is horizontal displacement x at time t?
- u t sin θ
- u t cos θ
- u t² cos θ
- u cos θ
-
In the cartesian trajectory equation y = x tan θ - gx²/(2u² cos² θ), what is the coefficient of x?
- tan θ
- sin θ
- cos θ
- sec θ
-
What is the total time of flight for a projectile launched at speed u at angle θ on flat ground?
- (u sin θ) / 2g
- (2 u cos θ) / g
- (2 u sin θ) / g
- (u sin θ) / g
-
Which launch angle gives the maximum horizontal range for a given initial speed on flat ground?
- 45 degrees
- 30 degrees
- 60 degrees
- 90 degrees
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