Lesson T2.2.3
T2.2.3 Rearranging formulae Quiz: KS3 Maths, Unit 2
20 questions
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Lesson T2.2.3, Rearranging formulae: 20 multiple choice questions for the KS3 Maths (National Curriculum), Unit 2: Algebra, written with Revision Ninja.
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The 20 questions
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Make x the subject of y = x + 7.
- x = 7 - y
- x = y - 7
- x = 7y
- x = y + 7
-
Make a the subject of b = 3a.
- a = b/3
- a = 3/b
- a = 3b
- a = b - 3
-
Make t the subject of v = u + at.
- t = v - u - a
- t = v/a - u
- t = (v - u)/a
- t = (u - v)/a
-
Make r the subject of A = πr².
- r = A/π²
- r = √(A/π)
- r = √(Aπ)
- r = A/π
-
Make x the subject of y = 2x - 5.
- x = (y + 5)/2
- x = (y - 5)/2
- x = 2y + 5
- x = y/2 - 5
-
Make c the subject of P = 2a + 2c.
- c = (P - a)/2
- c = P/2 - a
- c = P/2 + a
- c = P - 2a
-
Make y the subject of 3x + 2y = 12.
- y = 6 - 3x
- y = 12 - 3x/2
- y = (12 - 3x)/2
- y = (3x - 12)/2
-
Make C the subject of F = 9C/5 + 32.
- C = 9(F - 32)/5
- C = 5F/9 + 32
- C = 5(F + 32)/9
- C = 5(F - 32)/9
-
Make m the subject of E = mc².
- m = √(E/c)
- m = E/c²
- m = Ec²
- m = E/c
-
Make d the subject of s = (d + 3)/2.
- d = s/2 - 3
- d = 2s - 3
- d = 2s + 3
- d = (s - 3)/2
-
Make b the subject of A = (a + b)h/2.
- b = A/h - a
- b = 2A/h + a
- b = 2A - a
- b = 2A/h - a
-
Make n the subject of m = 4n - 1.
- n = m/4 + 1
- n = (m + 1)/4
- n = (m - 1)/4
- n = 4m + 1
-
Make x the subject of y = 3/x.
- x = y/3
- x = 3/y
- x = y - 3
- x = 3y
-
Make w the subject of V = lwh.
- w = lh/V
- w = Vlh
- w = V/(lh)
- w = V - lh
-
Make x the subject of a(x + b) = c.
- x = c/(ab)
- x = (c - b)/a
- x = c - ab
- x = c/a - b
-
A cost is C = 12 + 3n. Make n the subject, then find n when C = 30.
- n = (C + 12)/3 and n = 14
- n = (C - 12)/3 and n = 6
- n = 3C - 12 and n = 78
- n = C/3 - 12 and n = -2
-
A speed formula is s = d/t. Make t the subject.
- t = d/s
- t = d - s
- t = s/d
- t = ds
-
Make x the subject of 2(x - 3) = y + 4.
- x = (y + 10)/2
- x = (y - 10)/2
- x = (y + 4)/2 - 3
- x = 2y + 10
-
Make u the subject of v² = u² + 2as.
- u = √(v² - 2as)
- u = √(v² + 2as)
- u = v² - 2as
- u = (v² - 2as)²
-
Make h the subject of V = (1/3)πr²h.
- h = V/(3πr²)
- h = 3V/(πr²)
- h = 3πr²/V
- h = Vπr²/3
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