Lesson 3.7.3.3
3.7.3.3 Electric potential Quiz: AQA Physics, Unit 7
20 questions
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Lesson 3.7.3.3, Electric potential: 20 multiple choice questions for the AQA Physics (7408), Unit 7: Fields and their consequences (A-level only), written with Revision Ninja.
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The 20 questions
-
The electric potential at a point is defined as:
- the work done per unit charge from the surface to the point
- the work done per unit positive charge in moving a small test charge from infinity to that point
- the energy stored per unit volume at the point
- the force per unit charge at the point
-
The zero of electric potential is taken to be:
- at infinity
- at the charge itself
- at the surface of the charge
- at the midpoint between two charges
-
The electric potential in a radial field at distance r from a point charge Q is:
- V = Q / (4 pi eps0 r^2)
- V = 4 pi eps0 Q / r
- V = Q r / (4 pi eps0)
- V = Q / (4 pi eps0 r)
-
The work done in moving a charge Q through a potential difference delta V is:
- delta W = delta V / Q
- delta W = Q delta V
- delta W = Q / delta V
- delta W = Q delta V^2
-
No work is done when moving a charge along an equipotential surface because:
- the potential difference is zero, so Q delta V = 0
- the surface is at infinity
- the force on the charge is zero along the surface
- the charge does not move
-
The relationship between field strength and potential gradient is:
- E = -delta V / delta r
- E = -delta r / delta V
- E = delta V delta r
- E = delta V / delta r^2
-
The electric potential of a positive point charge is:
- negative
- zero
- positive
- infinite at every distance
-
A point charge of 2.0 nC is at a distance of 0.50 m. What is the electric potential at this point?
- about 9.0 V
- about 144 V
- about 4.0 V
- about 36 V
-
A charge of 1.0 microcoulomb is moved from 1.0 m to 0.50 m from a 4.0 microcoulomb point charge. How much work is done?
- about 3.6 J
- about 0.072 J
- about 0.0036 J
- about 0.036 J
-
A pd of 40 V exists across two points 0.20 m apart in a uniform field. What is the field strength?
- 2000 V m^-1
- 200 V m^-1
- 0.005 V m^-1
- 8.0 V m^-1
-
An electron is accelerated through a pd of 500 V. What kinetic energy does it gain, in joules? Take e = 1.6 x 10^-19 C.
- 3.2 x 10^-19 J
- 8.0 x 10^-19 J
- 1.6 x 10^-16 J
- 8.0 x 10^-17 J
-
Two positive point charges of 1.0 nC are each 0.30 m from point P. Estimate the potential at P.
- zero
- about 60 V
- about 120 V
- about 30 V
-
On a graph of potential V against distance r from a point charge, the gradient equals:
- k Q
- minus the field strength, -E
- Q
- E
-
A +4.0 nC and a -4.0 nC point charge are placed 0.20 m apart. What is the electric potential at the midpoint between them?
- zero
- about -360 V
- about 360 V
- about 720 V
-
An electron moves from 1.0 cm to 2.0 cm from a +1.0 microcoulomb point charge. What is the change in its electrostatic potential energy?
- about +7.2 x 10^-19 J
- about -7.2 x 10^-14 J
- about +1.4 x 10^-13 J
- about +7.2 x 10^-14 J
-
A student says potential is greatest where field strength is greatest. Which response is best?
- Incorrect: potential is always zero near any charge.
- Incorrect: field strength is the negative gradient of potential, so a strong field can occur where the potential is low, and zero field can occur where the potential is high.
- Correct: potential and field strength always rise together.
- Correct, because E = V d for any field.
-
An electron is accelerated through 1.2 kV. How much energy does it gain, in joules?
- about 1.9 x 10^-16 J
- about 1.2 x 10^-16 J
- about 1.9 x 10^-19 J
- about 7.5 x 10^-16 J
-
The potential difference between two points is:
- the charge passing per unit time between them
- the force per unit distance between them
- the work done per unit charge in moving a charge between them
- the field strength multiplied by the charge
-
The potential difference between two points is 12 V. How much work is done in moving 0.50 C between them?
- 24 J
- 12.5 J
- 6.0 J
- 0.042 J
-
An electron moves from a point at +30 V to a point at +10 V. Its electrostatic potential energy:
- is unchanged
- increases by 4.8 x 10^-18 J
- increases by 3.2 x 10^-18 J
- decreases by 3.2 x 10^-18 J
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