Lesson DF5-DF6
DF5-DF6 Optimal mixed strategies and linear programming Quiz: AQA Further Maths, Unit 5
20 questions
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Lesson DF5-DF6, Optimal mixed strategies and linear programming: 20 multiple choice questions for the AQA Further Maths (7367), Unit 5: Optional application 3: discrete mathematics, written with Revision Ninja.
Host it live on the board and students join with a game code on their own devices, or revise alone with Free Play. The answers are revealed in the game.
The 20 questions
-
What is a mixed strategy in a zero-sum game?
- A strategy in which a player chooses each pure option with a set probability, randomising the choice over repeated play
- A strategy in which a player always chooses the option with the largest entry
- A strategy in which a player picks two options at once in a single play
- A strategy in which a player always chooses the middle option
-
What makes a mixed strategy optimal for a player?
- It gives the best guaranteed expected payoff whatever the opponent does
- It is a strategy that the opponent is forced to use
- It gives equal probability to every option, so it is always fair
- It gives the highest payoff against one specific opponent option only
-
In the graphical method for a 2 × n zero-sum game, what is plotted and what is sought?
- The payoff matrix is drawn as a bar chart and the tallest bar is read off
- The expected payoff against each column is plotted against the probability of one row, and the highest point of the lower envelope is found
- The payoff for each row is plotted against the column probability, and the lowest point of the upper envelope is found
- A line through the origin is drawn for each strategy and where it meets the axis is read off
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 1 3; A2: 4 2, and columns B1, B2. What is the value of this game?
- 3
- 2.5
- 2
- 3.5
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 1 3; A2: 4 2, and columns B1, B2. What probability should the row player assign to A1 in an optimal mixed strategy?
- 0.4
- 0.25
- 0.5
- 0.75
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 4 0 3; A2: 1 3 2, and columns B1, B2, B3. What is the value of this game?
- 1.5
- 2.25
- 2
- 3
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 4 0 3; A2: 1 3 2, and columns B1, B2, B3. What optimal mixed strategy should the row player use?
- A1 with probability 2/3 and A2 with probability 1/3
- A1 with probability 1/2 and A2 with probability 1/2
- A1 with probability 1/4 and A2 with probability 3/4
- A1 with probability 1/3 and A2 with probability 2/3
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 4 0 3; A2: 1 3 2, and columns B1, B2, B3. Which columns does the column player use in an optimal mixed strategy?
- Columns B2 and B3 only, since their lines meet at the optimal point
- Column B3 only, since it has the largest entries
- All three columns with equal probability
- Columns B1 and B2 only, since their lines meet at the optimal point
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 4 0 3; A2: 1 3 2, and columns B1, B2, B3. In an optimal mixed strategy for the column player, what probability is assigned to column B1?
- 1/3
- 0.5
- 2/3
- 0.25
-
To solve a zero-sum game as a linear programme, what does the row player's problem look like?
- Minimise v subject to each row's expected payoff being at most v
- Maximise v subject to each row's expected payoff being at most v
- Maximise the sum of the probabilities subject to every entry being at most v
- Maximise v subject to each column's expected payoff being at least v, with the probabilities summing to 1 and non-negative
-
Why must the probabilities in a mixed strategy sum to 1?
- Because the value of every game is always 1
- Because a mixed strategy is a probability distribution over the pure strategies, so the probabilities must total 1
- So that the value of the game equals the sum of all the entries
- So that the column player's probabilities are then equal
-
A 3 × 3 zero-sum game is solved as a linear programme for the row player. How many constraints, excluding non-negativity and the probability sum, are there?
- 2, one fewer than the number of rows
- 9, one for each entry of the matrix
- 3, one for each column of the pay-off matrix
- 1, the probability sum constraint only
-
A 2 × 2 zero-sum game has a saddle point. What are its optimal strategies?
- Pure strategies, with the saddle row and saddle column each played with probability 1
- There are no optimal strategies for a game with a saddle point
- Both rows played with probability 1/2
- Each row played with a probability equal to its maximin value
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 3 -1; A2: -2 4, and columns B1, B2. In an optimal mixed strategy for the column player, what probability does B1 receive?
- 0.4
- 0.5
- 0.3
- 0.6
-
Why do the optimal mixed strategies of both players give the same value?
- Because the value is the single payoff at which the maximin and minimax of the mixed game coincide
- Because the row player's payoffs are always larger than the column player's
- Because mixed strategies always assign equal probabilities
- Because the value depends only on the number of rows and columns
-
A calculation gives a probability p = 1.2 for row A1 in a 2 × 2 game. What does this indicate?
- The value of the game must then be 1.2
- The row player should play A1 more than all the time, which is allowed
- The calculation is wrong, since probabilities must lie between 0 and 1
- The row player should play A2 with probability -0.2 for a better result
-
Which statement about the graphical solution of a 2 × n game is correct?
- The optimum occurs at the lowest point of the upper envelope of the column lines
- The graph gives the column player's probabilities directly without any calculation
- The optimum occurs at the highest point of the lower envelope of the column lines, usually where two of them meet
- The optimum is always at p = 0 or p = 1
-
A game has an optimal mixed strategy that uses only two of its three rows. Why might the third row be excluded?
- Because every row must be used in an optimal mixed strategy
- Because the excluded row has the largest entry in the matrix
- Because a probability of zero means the game has no value
- Because it is not needed for the optimum, since the remaining rows already give the guaranteed value
-
A zero-sum game has pay-off matrix (gains to the row player A) with rows A1: 1 3; A2: 4 2, and columns B1, B2. If the row player uses A1 with probability 0.25 and A2 with probability 0.75, what is the expected payoff against column B1?
- 2.75
- 2.5
- 3.75
- 3.25
-
In an optimal mixed strategy, what must be equal across the opponent's pure strategies that are actually used?
- The expected payoff against each of them, which equals the value of the game
- The probability assigned to each pure strategy
- The difference between the row minima of the matrix
- The largest entry in the pay-off matrix
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