Lesson D8-D10
D8-D10 Polynomial, rational and modulus inequalities Quiz: AQA Further Maths, Unit 2
20 questions
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Lesson D8-D10, Polynomial, rational and modulus inequalities: 20 multiple choice questions for the AQA Further Maths (7367), Unit 2: Compulsory content, written with Revision Ninja.
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The 20 questions
-
Solve x(x - 2)(x + 1) > 0.
- 0 < x < 2 only
- -1 < x < 0 or x > 2
- x < -1 or 0 < x < 2
- x < -1 or x > 2
-
What is the definition of |x|?
- Always negative
- x if x < 0, and -x if x >= 0
- x if x >= 0, and -x if x < 0
- x^2 for all x
-
Solve |x| < 3.
- x = 3 or x = -3
- x > 3 or x < -3
- -3 < x < 3
- x < 3 only
-
Solve x^2 - 3x - 4 < 0.
- 1 < x < 4
- x < -1 or x > 4
- -1 < x < 4
- -4 < x < 1
-
Solve (x - 1)/(x + 2) > 0.
- x > -2 only, since the denominator is positive for every value above -2
- x < 1 only, since the numerator is negative for every value below 1
- -2 < x < 1, since the fraction is positive between its critical values
- x < -2 or x > 1
-
Solve |2x - 1| <= 5.
- -3 <= x <= 2
- -2 <= x <= 3
- -2 <= x < 3
- x <= -2 or x >= 3
-
Solve |x - 2| > |x + 1|.
- x > 2
- x < 1/2
- x > 1/2
- x < -1/2
-
Solve x^3 - x > 0.
- -1 < x < 1
- x > 0 only
- x < -1 or 0 < x < 1
- -1 < x < 0 or x > 1
-
Solve x^3 - 6x^2 + 11x - 6 >= 0.
- x <= 1 or 2 <= x <= 3
- 1 <= x <= 3
- 1 <= x <= 2 or x >= 3
- x >= 2 only
-
Solve (x^2 + 1)/(x - 1) < 0.
- x < -1
- x < 1
- x > 1
- All real x
-
Solve |x + 1| + |x - 2| = 5.
- x = 2 or x = -1
- x = 3 only
- x = -2 or x = 2
- x = -2 or x = 3
-
Solve x^4 - 5x^2 + 4 < 0.
- |x| > 1
- -2 < x < 2
- 1 < |x| < 2
- |x| < 1 or |x| > 2
-
Solve 2/x < 1.
- x = 2 only, since the fraction equals 1 at that single point
- x < 0 or x > 2
- x > 2 only, since the fraction is less than 1 only for large positive x
- 0 < x < 2, since the fraction is less than 1 between 0 and 2
-
Solve |x - 1| < |2x + 1|.
- x > 0 only, since the modulus on the right is always larger
- x < -2 only, since the left side is larger for every value below -2
- x < -2 or x > 0
- -2 < x < 0, since the two modulus expressions cross at these values
-
Find the values of k for which x^2 + kx + 4 > 0 for all real x.
- k < -4 or k > 4
- -4 < k < 4
- 0 < k < 4
- k > 4 only
-
Solve x/(x + 1) >= 2.
- -1 < x <= 2
- x <= -2 or x > -1
- -2 <= x < -1
- -2 < x <= -1
-
Solve |x^2 - 4| < 5.
- x < -3 or x > 3
- -sqrt(5) < x < sqrt(5)
- -3 < x < 3
- -1 < x < 1
-
Solve (x - 2)^2 (x + 1) <= 0.
- x <= -1 or x = 2
- x >= -1 or x = 2
- x <= -1 only
- -1 <= x <= 2
-
Solve x^4 - 3x^2 - 4 > 0.
- x < -2 or x > 2
- x < -2 or 0 < x < 2
- -2 < x < 2
- x > 2 only
-
How many integer values of x satisfy |2x - 3| < 6?
- 7
- 9
- 6
- 5
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